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std::move_backward

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Revision as of 14:33, 6 September 2013 by P12 (Talk | contribs)

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Defined in header <algorithm>
template< class BidirIt1, class BidirIt2 >
BidirIt2 move_backward( BidirIt1 first, BidirIt1 last, BidirIt2 d_last );
(since C++11)

Moves the elements from the range [first, last), to another range ending at d_last. The elements are moved in reverse order (the last element is moved first), but their relative order is preserved.

The behavior is undefined if d_last is within (first, last]. std::move must be used instead of std::move_backward in that case.

Contents

[edit] Parameters

first, last - the range of the elements to move
d_last - end of the destination range
Type requirements
-
BidirIt1, BidirIt2 must meet the requirements of BidirectionalIterator.

[edit] Return value

Iterator in the destination range, pointing at the last element moved.

[edit] Complexity

Exactly last - first move assignments.

[edit] Possible implementation

template< class BidirIt1, class BidirIt2 >
BidirIt2 move_backward(BidirIt1 first,
                                     BidirIt1 last,
                                     BidirIt2 d_last)
{
    while (first != last) {
        *(--d_last) = std::move(*(--last));
    }
    return d_last;
}

[edit] Notes

When moving overlapping ranges, std::move is appropriate when moving to the left (beginning of the destination range is outside the source range) while std::move_backward is appropriate when moving to the right (end of the destination range is outside the source range).

[edit] Example

#include <algorithm>
#include <vector>
#include <string>
#include <iostream>
 
int main()
{
    std::vector<std::string> src{"foo", "bar", "baz"};
    std::vector<std::string> dest(src.size());
 
    std::cout << "src: ";
    for (const auto &s : src)
    {
        std::cout << s << ' ';
    }   
    std::cout << "\ndest: ";
    for (const auto &s : dest)
    {
        std::cout << s << ' ';
    }   
    std::cout << '\n';
 
    std::move_backward(src.begin(), src.end(), dest.end());
 
    std::cout << "src: ";                                                       
    for (const auto &s : src)
    {
        std::cout << s << ' ';
    }   
    std::cout << "\ndest: ";
    for (const auto &s : dest)
    {
        std::cout << s << ' ';
    }   
    std::cout << '\n';
}

Output:

src: foo bar baz 
dest:    
src:    
dest: foo bar baz

[edit] See also

(C++11)
moves a range of elements to a new location
(function template) [edit]