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std::list::erase

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Revision as of 20:33, 2 November 2012 by P12bot (Talk | contribs)

(1)
iterator erase( iterator pos );
(until C++11)
iterator erase( const_iterator pos );
(since C++11)
(2)
iterator erase( iterator first, iterator last );
(until C++11)
iterator erase( const_iterator first, const_iterator last );
(since C++11)

Removes specified elements from the container.

1) Removes the element at pos.
2) Removes the elements in the range [first; last).

References and iterators to the erased elements are invalidated. Other references and iterators are not affected.

The iterator pos must be valid and dereferenceable. Thus the end() iterator (which is valid, but is not dereferencable) cannot be used as a value for pos.

Contents

Parameters

pos - iterator to the element to remove
first, last - range of elements to remove

Return value

Iterator following the last removed element.

Example

#include <list>
#include <iostream>
#include <iterator>
 
int main( )
{
    std::list<int> c{0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
    for (auto &i : c) {
        std::cout << i << " ";
    }
    std::cout << '\n';
 
    c.erase(c.begin());
 
    for (auto &i : c) {
        std::cout << i << " ";
    }
    std::cout << '\n';
 
    std::list<int>::iterator range_begin = c.begin();
    std::list<int>::iterator range_end = c.begin();
    std::advance(range_begin,2);
    std::advance(range_end,5);
 
    c.erase(range_begin, range_end);
 
    for (auto &i : c) {
        std::cout << i << " ";
    }
    std::cout << '\n';
}

Output:

0 1 2 3 4 5 6 7 8 9
1 2 3 4 5 6 7 8 9
1 2 6 7 8 9

Complexity

1) Constant.
2) Linear in the distance between first and last.

See also

clears the contents
(public member function) [edit]