pointer allocate( size_type n, std::allocator<void>::const_pointer hint = 0 );
Allocates n * sizeof(T) bytes of uninitialized storage by calling ::operator new(std::size_t), but it is unspecified when and how this function is called. The pointer
hint may be used to provide locality of reference: the allocator, if supported by the implementation, will attempt to allocate the new memory block as close as possible to
|n||-||the number of objects to allocate storage for|
|hint||-||pointer to a nearby memory location|
Pointer to the first byte of a memory block suitably aligned and sufficient to hold an array of
n objects of type
Throws std::bad_alloc if allocation fails.