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std::enable_shared_from_this::operator=

From cppreference.com
 
 
 
 
 
enable_shared_from_this<T>& operator=(const enable_shared_from_this<T> &obj) noexcept;

Does nothing; returns *this.

Contents

Parameters

obj - an enable_shared_from_this to assign to *this

Return value

*this

Exceptions

noexcept specification:  
noexcept
  

Example

Note: enable_shared_from_this::operator= is defined as protected in order to prevent accidental slicing but allow derived classes to have default assignment operators.

#include <memory>
#include <iostream>
 
class SharedInt : public std::enable_shared_from_this<SharedInt>
{
public:
    explicit SharedInt(int n) : mNumber(n) {}
    SharedInt(const SharedInt&) = default;
    SharedInt(SharedInt&&) = default;
    ~SharedInt() = default;
 
    // Both assignment operators use enable_shared_from_this::operator=
    SharedInt& operator=(const SharedInt&) = default;
    SharedInt& operator=(SharedInt&&) = default;
 
    int number() const { return mNumber; }
 
private:
    int mNumber;
};
 
int main() {
    std::shared_ptr<SharedInt> a = std::make_shared<SharedInt>(2);
    std::shared_ptr<SharedInt> b = std::make_shared<SharedInt>(4);
    *a = *b;
 
    std::cout << a->number() << std::endl;
}

Output:

4

See also

smart pointer with shared object ownership semantics
(class template) [edit]