Assignment operators
Assignment and compound assignment operators are binary operators that modify the variable to their left using the value to their right.
Operator  Operator name  Example  Description  Equivalent of 

=  basic assignment  a = b  a becomes equal to b  N/A 
+=  addition assignment  a += b  a becomes equal to the addition of a and b  a = a + b 
=  subtraction assignment  a = b  a becomes equal to the subtraction of b from a  a = a  b 
*=  multiplication assignment  a *= b  a becomes equal to the product of a and b  a = a * b 
/=  division assignment  a /= b  a becomes equal to the division of a by b  a = a / b 
%=  modulo assignment  a %= b  a becomes equal to the remainder of a divided by b  a = a % b 
&=  bitwise AND assignment  a &= b  a becomes equal to the bitwise AND of a and b  a = a & b 
=  bitwise OR assignment  a = b  a becomes equal to the bitwise OR of a and b  a = a  b 
^=  bitwise XOR assignment  a ^= b  a becomes equal to the bitwise XOR of a and b  a = a ^ b 
<<=  bitwise left shift assignment  a <<= b  a becomes equal to a left shifted by b  a = a << b 
>>=  bitwise right shift assignment  a >>= b  a becomes equal to a right shifted by b  a = a >> b 
Contents 
[edit] Simple assignment
The simple assignment operator expressions have the form
lhs = rhs


where
lhs    modifiable lvalue expression of any complete object type 
rhs    expression of any type implicitly convertible to lhs or compatible with lhs 
Assignment performs implicit conversion from the value of rhs to the type of rhs and then replaces the value in the object designated by lhs with the converted value of rhs.
Assignment also returns the same value (so that expressions such as a = b = c are possible). The value category of the assignment operator is nonlvalue (so that expressions such as (a=b)=c are invalid).
rhs and lhs must satisfy one of the following:
 both lhs and rhs have compatible struct or union type, or..
 rhs must be implicitly convertible to lhs, which implies
 both lhs and rhs have arithmetic types, in which case lhs may be volatilequalified or atomic
 both lhs and rhs have pointer to compatible (ignoring qualifiers) types, or one of the pointers is a pointer to void, and the conversion would not add qualifiers to the pointedto type. lhs may be volatile or restrictqualified or atomic.
 lhs is a pointer (possibly qualified or atomic) and rhs is a null pointer constant such as NULL
 lhs has type _Bool (possibly qualified or atomic) and rhs is a pointer
[edit] Notes
If rhs and lhs overlap in memory (e.g. they are members of the same union), the behavior is undefined unless the overlap is exact and the types are compatible.
Although arrays are not assignable, an array wrapped in a struct is assignable to another object of the same (or compatible) struct type.
The side effect of updating lhs is sequenced after the value computations, but not the side effects of lhs and rhs themselves and the evaluations of the operands are, as usual, unsequenced relative to each other (so the expressions such as i=++i; are undefined)
Assignment strips extra range and precision from floatingpoint expressions (see FLT_EVAL_METHOD
In C++, assignment operators are lvalue expressions, not so in C
// todo more, demo struct{array} too const char **cpp; char *p; const char c = 'A'; cpp = &p; // Error: char ** is not convertible to const char ** *cpp = &c; // OK, char* is convertible to const char* *p = 0; // OK, null pointer constant is convertible to any pointer
[edit] Compound assignment
The compound assignment operator expressions have the form
lhs op rhs  
where
op    one of *=, /= %=, += =, <<=, >>=, &=, ^=, = 
lhs, rhs    expressions with arithmetic types (where lhs may be qualified or atomic), except when op is += or =, which also accept pointer types with the same restrictions as + and  
The expression lhs @= rhs is exactly the same as lhs =
lhs @ (
rhs )
, except that lhs is evaluated only once.
If lhs has atomic type, the operation behaves as a single atomic readmodifywrite operation with memory order memory_order_seq_cst For integer atomic types, the compound assignment @= is equivalent to: T1* addr = &lhs; T2 val = rhs; T1 old = *addr; T1 new; do { new = old @ val } while (!atomic_compare_exchange_strong(addr, &old, new); 
(since C11) 
This section is incomplete Reason: no example 
[edit] See Also
Common operators  

assignment  increment decrement 
arithmetic  logical  comparison  member access 
other 
a = b 
++a 
+a 
!a 
a == b 
a[b] 
a(...) 