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std::literals::chrono_literals::operator""h

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< cpp‎ | chrono
 
 
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Defined in header <chrono>
constexpr std::chrono::hours
    operator""h( unsigned long long hrs );
(1) (since C++14)
constexpr std::chrono::duration</*unspecified*/, std::ratio<3600,1>>
    operator""h( long double hrs );
(2) (since C++14)

Forms a std::chrono::duration literal representing hours.

1) Integer literal, returns exactly std::chrono::hours(hrs).
2) Floating-point literal, returns a floating-point duration equivalent to std::chrono::hours.

Contents

[edit] Parameters

hrs - the number of hours

[edit] Return value

The std::chrono::duration literal.

[edit] Possible implementation

constexpr std::chrono::hours operator""h(unsigned long long h)
{
    return std::chrono::hours(h);
}
 
constexpr std::chrono::duration<long double, ratio<3600,1>> operator""h(long double h)
{
    return std::chrono::duration<long double, std::ratio<3600,1>>(h);
}

[edit] Notes

This operator is declared in the namespace std::literals::chrono_literals, where both literals and chrono_literals are inline namespaces. Access to this operator can be gained with:

  • using namespace std::literals,
  • using namespace std::chrono_literals, or
  • using namespace std::literals::chrono_literals.

In addition, within the namespace std::chrono, the directive using namespace literals::chrono_literals; is provided by the standard library, so that if a programmer uses using namespace std::chrono; to gain access to the classes in the chrono library, the corresponding literal operators become visible as well.

[edit] Example

#include <chrono>
#include <iostream>
 
int main()
{
    using namespace std::chrono_literals;
    auto day = 24h;
    auto halfhour = 0.5h;
    std::cout << "one day is " << day.count() << " hours (" << day << ")\n"
              << "half an hour is " << halfhour.count() << " hours ("
              << halfhour << ")\n";
}

Output:

one day is 24 hours (24h)
half an hour is 0.5 hours (0.5h)

[edit] See also

constructs new duration
(public member function of std::chrono::duration<Rep,Period>) [edit]