deduction guides for std::deque

< cpp‎ | container‎ | deque
Defined in header <deque>
template< class InputIt,

          class Alloc = std::allocator<typename std::iterator_traits<InputIt>::value_type>>
deque(InputIt, InputIt, Alloc = Alloc())

  -> deque<typename std::iterator_traits<InputIt>::value_type, Alloc>;
(since C++17)

This deduction guide is provided for deque to allow deduction from an iterator range. This overload only participates in overload resolution if InputIt satisfies InputIterator and Alloc satisfies Allocator.

Note: the extent to which the library determines that a type does not satisfy InputIterator is unspecified, except that as a minimum integral types do not qualify as input iterators. Likewise, the extent to which it determines that a type does not satisfy Allocator is unspecified, except that as a minimum the member type Alloc::value_type must exist and the expression std::declval<Alloc&>().allocate(std::size_t{}) must be well-formed when treated as an unevaluated operand.

[edit] Example

#include <deque>
#include <vector>
int main() {
   std::vector<int> v = {1, 2, 3, 4};
   // uses explicit deduction guide to deduce std::deque<int>
   std::deque x(v.begin(), v.end()); 
   // deduces std::deque<std::vector<int>::iterator>
   // first phase of overload resolution for list-initialization selects the candidate
   // synthesized from the initializer-list constructor; second phase is not performed and
   // deduction guide has no effect
   std::deque y{v.begin(), v.end()};