void deallocate( T* p, std::size_t n );
Deallocates the storage referenced by the pointer
p, which must be a pointer obtained by an earlier call to allocate().
n must be equal to the first argument of the call to allocate() that originally produced
p; otherwise, the behavior is undefined.
Calls ::operator delete(void*), but it is unspecified when and how it is called.
|p||-|| pointer obtained from |
|n||-|| number of objects earlier passed to |
 Return value
 See also
| allocates uninitialized storage |
(public member function)
| deallocates storage using the allocator |
(public static member function of