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std::exp, std::expf, std::expl

From cppreference.com
< cpp‎ | numeric‎ | math
 
 
 
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Defined in header <cmath>
(1)
float       exp ( float num );

double      exp ( double num );

long double exp ( long double num );
(until C++23)
/* floating-point-type */
            exp ( /* floating-point-type */ num );
(since C++23)
(constexpr since C++26)
float       expf( float num );
(2) (since C++11)
(constexpr since C++26)
long double expl( long double num );
(3) (since C++11)
(constexpr since C++26)
Additional overloads (since C++11)
Defined in header <cmath>
template< class Integer >
double      exp ( Integer num );
(A) (constexpr since C++26)
1-3) Computes e (Euler's number, 2.7182818...) raised to the given power num. The library provides overloads of std::exp for all cv-unqualified floating-point types as the type of the parameter.(since C++23)
A) Additional overloads are provided for all integer types, which are treated as double.
(since C++11)

Contents

[edit] Parameters

num - floating-point or integer value

[edit] Return value

If no errors occur, the base-e exponential of num (enum
) is returned.

If a range error occurs due to overflow, +HUGE_VAL, +HUGE_VALF, or +HUGE_VALL is returned.

If a range error occurs due to underflow, the correct result (after rounding) is returned.

[edit] Error handling

Errors are reported as specified in math_errhandling.

If the implementation supports IEEE floating-point arithmetic (IEC 60559),

  • If the argument is ±0, 1 is returned.
  • If the argument is -∞, +0 is returned.
  • If the argument is +∞, +∞ is returned.
  • If the argument is NaN, NaN is returned.

[edit] Notes

For IEEE-compatible type double, overflow is guaranteed if 709.8 < num, and underflow is guaranteed if num < -708.4.

The additional overloads are not required to be provided exactly as (A). They only need to be sufficient to ensure that for their argument num of integer type, std::exp(num) has the same effect as std::exp(static_cast<double>(num)).

[edit] Example

#include <cerrno>
#include <cfenv>
#include <cmath>
#include <cstring>
#include <iomanip>
#include <iostream>
#include <numbers>
 
// #pragma STDC FENV_ACCESS ON
 
consteval double approx_e()
{
    long double e{1.0};
    for (auto fac{1ull}, n{1llu}; n != 18; ++n, fac *= n)
        e += 1.0 / fac;
    return e;
}
 
int main()
{
    std::cout << std::setprecision(16)
              << "exp(1) = e¹ = " << std::exp(1) << '\n'
              << "numbers::e  = " << std::numbers::e << '\n'
              << "approx_e    = " << approx_e() << '\n'
              << "FV of $100, continuously compounded at 3% for 1 year = "
              << std::setprecision(6) << 100 * std::exp(0.03) << '\n';
 
    // special values
    std::cout << "exp(-0) = " << std::exp(-0.0) << '\n'
              << "exp(-Inf) = " << std::exp(-INFINITY) << '\n';
 
    // error handling 
    errno = 0;
    std::feclearexcept(FE_ALL_EXCEPT);
 
    std::cout << "exp(710) = " << std::exp(710) << '\n';
 
    if (errno == ERANGE)
        std::cout << "    errno == ERANGE: " << std::strerror(errno) << '\n';
    if (std::fetestexcept(FE_OVERFLOW))
        std::cout << "    FE_OVERFLOW raised\n";
}

Possible output:

exp(1) = e¹ = 2.718281828459045
numbers::e  = 2.718281828459045
approx_e    = 2.718281828459045
FV of $100, continuously compounded at 3% for 1 year = 103.045
exp(-0) = 1
exp(-Inf) = 0
exp(710) = inf
    errno == ERANGE: Numerical result out of range
    FE_OVERFLOW raised

[edit] See also

(C++11)(C++11)(C++11)
returns 2 raised to the given power (2x)
(function) [edit]
(C++11)(C++11)(C++11)
returns e raised to the given power, minus one (ex-1)
(function) [edit]
(C++11)(C++11)
computes natural (base e) logarithm (ln(x))
(function) [edit]
complex base e exponential
(function template) [edit]
applies the function std::exp to each element of valarray
(function template) [edit]