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Defined in header <type_traits>
template< class... T >
struct common_type;
(since C++11)

Determines the common type among all types T..., that is the type all T... can be implicitly converted to. If such a type exists (as determined according to the rules below), the member type names that type. Otherwise, there is no member type.

  • If sizeof...(T) is zero, there is no member type.
  • If sizeof...(T) is one (i.e., T... contains only one type T0), the member type names the same type as std::decay<T0>::type.
  • If sizeof...(T) is two (i.e., T... contains exactly two types T1 and T2),
  • If applying std::decay to at least one of T1 and T2 produces a different type, the member type names the same type as common_type<std::decay<T1>::type, std::decay<T2>::type>::type, if it exists; if not, there is no member type.
  • Otherwise, unless there is a user specialization for common_type<T1, T2>, the member type denotes the type std::decay<decltype(false ? std::declval<T1>() : std::declval<T2>())>::type, if that conditional expression is well-formed; if not, there is no member type.
  • If sizeof...(T) is greater than two (i.e., T... consists of the types T1, T2, R...), then if common_type<T1, T2>::type exists, the member type denotes common_type<common_type<T1, T2>::type, R...>::type if such a type exists. In all other cases, there is no member type.

The types in the parameter pack T shall each be a complete type, (possibly cv-qualified) void, or an array of unknown bound. Otherwise, the behavior is undefined.


[edit] Member types

Name Definition
type the common type for all T...

[edit] Helper types

template< class... T >
using common_type_t = typename common_type<T...>::type;
(since C++14)

[edit] Specializations

Users may specialize common_type for distinct types T1 and T2 if

  • At least one of T1 and T2 depends on a user-defined type, and
  • std::decay is an identity transformation for both T1 and T2.

If such a specialization has a member named type, it must be a public and unambiguous member type that names a cv-unqualified non-reference type to which both T1 and T2 are explicitly convertible. Additionally, common_type<T1, T2>::type and common_type<T2, T1>::type must denote the same type.

A program that adds common_type specializations in violation of these rules has undefined behavior.

Note that the behavior of a program that adds a specialization to any other template from <type_traits> is undefined.

The following specializations are already provided by the standard library:

specializes the std::common_type trait
(class template specialization) [edit]
specializes the std::common_type trait
(class template specialization) [edit]

[edit] Possible implementation

// primary template (used for zero types)
template <class ...T> struct common_type { }; 
//////// one type
template <class T>
struct common_type<T> {
    using type = std::decay_t<T>;
//////// two types
// default implementation for two types
template<class T1, class T2>
using cond_t = decltype(false ? std::declval<T1>() : std::declval<T2>());
template<class T1, class T2, class=void>
struct common_type_2_default { };
template<class T1, class T2>
struct common_type_2_default<T1, T2, std::void_t<cond_t<T1, T2>>> {
    using type = std::decay_t<cond_t<T1, T2>>;
// dispatcher to decay the type before applying specializations
template<class T1, class T2, class D1 = std::decay_t<T1>, class D2=std::decay_t<T2>>
struct common_type_2_impl : common_type<D1, D2> {};
template<class D1, class D2>
struct common_type_2_impl<D1, D2, D1, D2> : common_type_2_default<D1, D2> {};
template <class T1, class T2>
struct common_type<T1, T2> : common_type_2_impl<T1, T2> { };
//////// 3+ types
template<class AlwaysVoid, class T1, class T2, class...R>
struct common_type_multi_impl { };
template< class T1, class T2, class...R>
struct common_type_multi_impl<std::void_t<common_type_t<T1, T2>>, T1, T2, R...>
    : common_type<common_type_t<T1, T2>, R...>  { };
template <class T1, class T2, class... R>
struct common_type<T1, T2, R...>
    : common_type_multi_impl<void, T1, T2, R...> { };

[edit] Notes

For arithmetic types not subject to promotion, the common type may be viewed as the type of the (possibly mixed-mode) arithmetic expression such as T0() + T1() + ... + Tn().

[edit] Defect reports

The following behavior-changing defect reports were applied retroactively to previously published C++ standards.

DR Applied to Behavior as published Correct behavior
LWG 2141 C++11 common_type<int, int>::type is int&& decayed result type
LWG 2408 C++11 common_type is not SFINAE-friendly made SFINAE-friendly
LWG 2460 C++11 common_type specializations are nearly impossible to write reduced number of specializations needed

[edit] Examples

Demonstrates mixed-mode arithmetic on a user-defined class

#include <iostream>
#include <type_traits>
template <class T>
struct Number { T n; };
template <class T, class U>
Number<typename std::common_type<T, U>::type> operator+(const Number<T>& lhs,
                                                        const Number<U>& rhs) 
    return {lhs.n + rhs.n};
int main()
    Number<int> i1 = {1}, i2 = {2};
    Number<double> d1 = {2.3}, d2 = {3.5};
    std::cout << "i1i2: " << (i1 + i2).n << "\ni1d2: " << (i1 + d2).n << '\n'
              << "d1i2: " << (d1 + i2).n << "\nd1d2: " << (d1 + d2).n << '\n';


i1i2: 3
i1d2: 4.5
d1i2: 4.3
d1d2: 5.8