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std::has_virtual_destructor

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Defined in header <type_traits>
template< class T >
struct has_virtual_destructor;
(since C++11)

If T is a type with a virtual destructor, provides the member constant value equal true. For any other type, value is false.

If T is a non-union class type, T shall be a complete type; otherwise, the behavior is undefined.

Contents

[edit] Helper variable template

template< class T >
inline constexpr bool has_virtual_destructor_v = has_virtual_destructor<T>::value;
(since C++17)

Inherited from std::integral_constant

Member constants

value
[static]
true if T has a virtual destructor , false otherwise
(public static member constant)

Member functions

operator bool
converts the object to bool, returns value
(public member function)
operator()
(C++14)
returns value
(public member function)

Member types

Type Definition
value_type bool
type std::integral_constant<bool, value>

[edit] Notes

If a class has a public virtual destructor, it can be derived from, and the derived object can be safely deleted through a pointer to the base object (GotW #18)

[edit] Example

#include <iostream>
#include <type_traits>
#include <string>
#include <stdexcept>
 
int main()
{
    std::cout << std::boolalpha
              << "std::string has a virtual destructor? "
              << std::has_virtual_destructor<std::string>::value << '\n'
              << "std::runtime_error has a virtual destructor? "
              << std::has_virtual_destructor<std::runtime_error>::value << '\n';
}

Output:

std::string has a virtual destructor? false
std::runtime_error has a virtual destructor? true

[edit] See also

checks if a type has a non-deleted destructor
(class template) [edit]