Talk:cpp/types/is function

All of the qualifiers (const, volatile, &, &&) only apply to member functions. As such they cannot be applied to a function, can they?

Microsoft's implementation does not accept them, but the libc++ implementation does.

Diltsman (talk) 18:05, 7 October 2015 (PDT)
 * They can, although the resulting type has limited uses. See [dcl.fct]/1-3, 6. T. Canens (talk) 18:43, 7 October 2015 (PDT)

too complicated implementation
Don't you think this implementation is too complicated? Why not using something like cpp/types/remove_cvref to simplify it?


 * Qualifiers on the member function qualifies the implicit object parameter, not the function itself, so they can neither be removed by nor be removed separately. Perhaps this implementation cannot be simplified. Fruderica (talk) 18:29, 8 February 2018 (PST)
 * There are ways to do it by SFINAE-ing on properties of function types, but for pedagogical purposes I'd rather keep the current implementation that nicely exhibits the myriad kinds of function types. T. Canens (talk) 18:48, 8 February 2018 (PST)

Args......?
What does mean? What's for this expansion of expansion? Riddler (talk) 14:40, 5 August 2021 (PDT)


 * it's a popular bar trivia question. Here's SO take on it: https://stackoverflow.com/q/5625600/273767 --Cubbi (talk) 15:19, 5 August 2021 (PDT)


 * It's mentioned here fyi --Ybab321 (talk) 02:40, 6 August 2021 (PDT)


 * +1 Local link dup to the same `double ellipsis` explanation (in case that "" ~Chromium extension is not pluged-in). --Space Mission (talk) 12:58, 6 August 2021 (PDT)