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std::chrono::year::is_leap

From cppreference.com
< cpp‎ | chrono‎ | year
 
 
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constexpr bool is_leap() const noexcept;
(since C++20)

Determines if *this represents a leap year in the proleptic Gregorian calendar.

*this represents a leap year if the stored year value

  • is divisible by 4 and not divisible by 100; or
  • is divisible by 400.

[edit] Return value

true if *this represents a leap year, otherwise false.

[edit] Example

#include <iostream>
#include <chrono>
 
int main()
{
    using namespace std::chrono_literals;
    for (const std::chrono::year y : {2020y, 2021y, 2000y, 3000y}) {
        std::cout << static_cast<int>(y) << " is "
                  << (y.is_leap() ? "" : "not ") << "a leap year\n";
    }
}

Output:

2020 is a leap year
2021 is not a leap year
2000 is a leap year
3000 is not a leap year