std::chrono::year::operator+=, std::chrono::year::operator-=

< cpp‎ | chrono‎ | year
Utilities library
Language support
Type support (basic types, RTTI)
Library feature-test macros (C++20)
Dynamic memory management
Program utilities
Coroutine support (C++20)
Variadic functions
Debugging support
Three-way comparison
General utilities
Date and time
Function objects
Formatting library (C++20)
Relational operators (deprecated in C++20)
Integer comparison functions
Swap and type operations
Common vocabulary types
Elementary string conversions

constexpr std::chrono::year& operator+=( const std::chrono::years& y ) noexcept;
(1) (since C++20)
constexpr std::chrono::year& operator-=( const std::chrono::years& y ) noexcept;
(2) (since C++20)

Adds or subtracts y.count() years from the year value.

1) Equivalent to *this = *this + y;.
2) Equivalent to *this = *this - y;.


[edit] Return value

A reference to this year after modification.

[edit] Notes

If the result would be outside the range [-3276732767], the actual stored value is unspecified.

[edit] Example

#include <chrono>
#include <iostream>
int main()
    using namespace std::literals::chrono_literals;
    std::cout << std::boolalpha;
    std::chrono::year y{2020};
    y += std::chrono::years(12);
    std::cout << (y == 2032y) << ' ';
    y -= std::chrono::years(33);
    std::cout << (y == 1999y) << '\n';


true true

[edit] See also

increments or decrements the year
(public member function) [edit]
performs arithmetic on years
(function) [edit]