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std::chrono::year_month_day::operator+=, std::chrono::year_month_day::operator-=

From cppreference.com
 
 
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C-style date and time
 
 
constexpr std::chrono::year_month_day& operator+=(const std::chrono::years& dy) const noexcept;
(1) (since C++20)
constexpr std::chrono::year_month_day& operator+=(const std::chrono::months& dm) const noexcept;
(2) (since C++20)
constexpr std::chrono::year_month_day& operator-=(const std::chrono::years& dy) const noexcept;
(3) (since C++20)
constexpr std::chrono::year_month_day& operator-=(const std::chrono::months& dm) const noexcept;
(4) (since C++20)

Modifies the time point *this represents by the duration dy or dm.

1) Equivalent to *this = *this + dy;
2) Equivalent to *this = *this + dm;
3) Equivalent to *this = *this - dy;
4) Equivalent to *this = *this - dm;

For durations that are convertible to both std::chrono::years and std::chrono::months, the years overloads (1,3) are preferred if the call would otherwise be ambiguous.

[edit] See also

adds or subtracts a year_month_day and some number of years or months
(public member function) [edit]

[edit] Example

#include <iostream>
#include <chrono>
 
int main()
{
    std::cout << std::boolalpha;
 
    constexpr auto monthsInYear {12};
    auto ymd {std::chrono::day(1)/std::chrono::July/2020};
 
    ymd -= std::chrono::years(10);
    std::cout << (ymd.month() == std::chrono::July) << ' '
              << (ymd.year() == std::chrono::year(2010)) << ' ';
 
    ymd += std::chrono::months(10 * monthsInYear + 11);
    std::cout << (ymd.month() == std::chrono::month(6)) << ' '
              << (ymd.year() == std::chrono::year(2021)) << ' ';
}

Output:

true true true true