std::chrono::year_month_day_last::operator sys_days, std::chrono::year_month_day_last::operator local_days

Utilities library
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constexpr operator std::chrono::sys_days() const noexcept;
(1) (since C++20)
constexpr explicit operator std::chrono::local_days() const noexcept;
(2) (since C++20)

Converts *this to a std::chrono::time_point representing the same date as this year_month_day_last. This is equivalent to composing a year_month_day from year(), month() and day() and converting that year_month_day to the destination type.

1) Equivalent to std::chrono::sys_days(year()/month()/day()).
2) Equivalent to std::chrono::local_days(year()/month()/day()).

[edit] Example

#include <array>
#include <chrono>
#include <iostream>
#include <string_view>
using namespace std::chrono;
using namespace std::literals;
int main()
    constexpr std::chrono::year y{2023y};
    constexpr std::array quarters{"1st"sv, "2nd"sv, "3rd"sv, "4th"sv};
    constexpr auto mq{12 / 4}; // months per quarter        
    std::cout << "In year " << static_cast<int>(y) << '\n';
    for (auto q = 1; q < 5; ++q)
        const auto ls = y / std::chrono::month(q * mq) / Sunday[last];
        const auto ld = y / std::chrono::month(q * mq) / last;
        // subtract last Sunday from last day for day of week
        const auto index = (sys_days(ld) - sys_days(ls)).count();
        std::cout << "The " << quarters[q - 1] << " quarter ends on a "  
                  << std::chrono::weekday(index) << '\n';


In year 2023
The 1st quarter ends on a Fri
The 2nd quarter ends on a Fri
The 3rd quarter ends on a Sat
The 4th quarter ends on a Sun

[edit] See also

converts to a std::chrono::time_point
(public member function of std::chrono::year_month_day) [edit]