std::chrono::year_month_weekday::operator sys_days, std::chrono::year_month_weekday::operator local_days

Utilities library
General utilities
Date and time
Function objects
Formatting library (C++20)
Relational operators (deprecated in C++20)
Integer comparison functions
Swap and type operations

Common vocabulary types

Elementary string conversions
constexpr operator std::chrono::sys_days() const noexcept;
(1) (since C++20)
explicit constexpr operator std::chrono::local_days() const noexcept;
(2) (since C++20)

Converts *this to a std::chrono::time_point representing the same date as this year_month_weekday.

1) If year().ok() && month().ok() && weekday().ok():
  • If index() == 0, returns a sys_days that represents the date 7 days prior to the first weekday() of the year and month.
  • Else, returns a sys_days that represents the date (index() - 1) * 7 days after the first weekday() of the year and month.
Otherwise, the returned value is unspecified.
2) Same as (1), but returns local_days instead of sys_days. Equivalent to local_days(sys_days(*this).time_since_epoch()).

[edit] Example

#include <iostream>
#include <chrono>
using namespace std::chrono;
int main()
    std::cout << std::boolalpha;
    constexpr auto ymwd {Tuesday[2]/11/2021};
    // convert from field-based to serial-based to add hours
    constexpr auto sd = sys_days{ymwd} + 24h;
    constexpr auto ymd = floor<days>(sd);
    std::cout << (ymd == November/10/2021) << '\n';