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std::erase, std::erase_if (std::list)

From cppreference.com
< cpp‎ | container‎ | list
Defined in header <list>
template< class T, class Alloc, class U >
void erase(std::list<T,Alloc>& c, const U& value);
(1) (since C++20)
template< class T, class Alloc, class Pred >
void erase_if(std::list<T,Alloc>& c, Pred pred);
(2) (since C++20)
1) Erases all elements that compare equal to value from the container. Equivalent to c.remove_if([&](auto& elem) { return elem == value; });
2) Erases all elements that satisfy the predicate pred from the container. Equivalent to c.remove_if(pred);

Contents

[edit] Parameters

c - container from which to erase
value - value to be removed
pred - unary predicate which returns ​true if the element should be erased.

The expression pred(v) must be convertible to bool for every argument v of type (possibly const) T, regardless of value category, and must not modify v. Thus, a parameter type of T&is not allowed, nor is T unless for T a move is equivalent to a copy (since C++11). ​

[edit] Complexity

Linear.

[edit] Example

#include <iostream>
#include <numeric>
#include <list>
 
void print_container(const std::list<char>& c)
{
    for (auto x : c) {
        std::cout << x << ' ';
    }
    std::cout << '\n';
}
 
int main()
{
    std::list<char> cnt(10);
    std::iota(cnt.begin(), cnt.end(), '0');
 
    std::cout << "Init:\n";
    print_container(cnt);
 
    std::erase(cnt, '5');
    std::cout << "Erase \'5\':\n";
    print_container(cnt);
 
    std::erase_if(cnt, [](char x) { return (x - '0') % 2 == 0; });
    std::cout << "Erase all even numbers:\n";
    print_container(cnt);
}

Output:

Init:
0 1 2 3 4 5 6 7 8 9 
Erase '5':
0 1 2 3 4 6 7 8 9 
Erase all even numbers:
1 3 7 9

Notes

Unlike std::list::remove, erase accepts heterogenous types and does not force a conversion to the container's value type before invoking the == operator.

[edit] See also

removes elements satisfying specific criteria
(function template) [edit]
removes elements satisfying specific criteria
(public member function) [edit]