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std::unordered_multimap<Key,T,Hash,KeyEqual,Allocator>::equal_range

From cppreference.com
 
 
 
 
std::pair<iterator,iterator> equal_range( const Key& key );
(1) (since C++11)
std::pair<const_iterator,const_iterator> equal_range( const Key& key ) const;
(2) (since C++11)
template< class K >
std::pair<iterator,iterator> equal_range( const K& x );
(3) (since C++20)
template< class K >
std::pair<const_iterator,const_iterator> equal_range( const K& x ) const;
(4) (since C++20)
1,2) Returns a range containing all elements with key key in the container. The range is defined by two iterators, the first pointing to the first element of the wanted range and the second pointing past the last element of the range.
3,4) Returns a range containing all elements in the container with key equivalent to x. This overload only participates in overload resolution if Hash::is_transparent and KeyEqual::is_transparent are valid and each denotes a type. This assumes that such Hash is callable with both K and Key type, and that the KeyEqual is transparent, which, together, allows calling this function without constructing an instance of Key.

Contents

[edit] Parameters

key - key value to compare the elements to
x - a value of any type that can be transparently compared with a key

[edit] Return value

std::pair containing a pair of iterators defining the wanted range. If there are no such elements, past-the-end (see end()) iterators are returned as both elements of the pair.

[edit] Complexity

Average case linear in the number of elements with the key key, worst case linear in the size of the container.

[edit] Example

#include <iostream>
#include <unordered_map>
 
int main()
{  
    std::unordered_multimap<int,char> map = {{1,'a'},{1,'b'},{1,'d'},{2,'b'}};
    auto range = map.equal_range(1);
    for (auto it = range.first; it != range.second; ++it) {
        std::cout << it->first << ' ' << it->second << '\n';
    }
}

Output:

1 a
1 b
1 d

[edit] See also

finds element with specific key
(public member function) [edit]