deduction guides for std::unordered_multiset
Defined in header <unordered_set>
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template< class InputIt, |
(1) | (since C++17) |
template< class T, class Hash = std::hash<T>, |
(2) | (since C++17) |
template< class InputIt, class Alloc > unordered_multiset( InputIt, InputIt, typename /* see below */::size_type, Alloc ) |
(3) | (since C++17) |
template< class InputIt, class Hash, class Alloc > unordered_multiset( InputIt, InputIt, typename /* see below */::size_type, Hash, Alloc ) |
(4) | (since C++17) |
template< class T, class Alloc > unordered_multiset( std::initializer_list<T>, typename /* see below */::size_type, Alloc ) |
(5) | (since C++17) |
template< class T, class Hash, class Alloc > unordered_multiset( std::initializer_list<T>, typename /* see below */::size_type, |
(6) | (since C++17) |
template< ranges::input_range R, class Hash = std::hash<ranges::range_value_t<R>>, |
(7) | (since C++23) |
template< ranges::input_range R, class Alloc > unordered_multiset( std::from_range_t, R&&, |
(8) | (since C++23) |
template< ranges::input_range R, class Alloc > unordered_multiset( std::from_range_t, R&&, Alloc ) |
(9) | (since C++23) |
template< ranges::input_range R, class Hash, class Alloc > unordered_multiset( std::from_range_t, R&&, |
(10) | (since C++23) |
unordered_multiset
to allow deduction from an iterator range (overloads (1,3,4)) and std::initializer_list (overloads (2,5,6)). This overload participates in overload resolution only if InputIt
satisfies LegacyInputIterator, Alloc
satisfies Allocator, neither Hash
nor Pred
satisfy Allocator, Hash
is not an integral type.unordered_multiset
to allow deduction from a std::from_range_t tag and an input_range
.Note: the extent to which the library determines that a type does not satisfy LegacyInputIterator is unspecified, except that as a minimum integral types do not qualify as input iterators. Likewise, the extent to which it determines that a type does not satisfy Allocator is unspecified, except that as a minimum the member type Alloc::value_type
must exist and the expression std::declval<Alloc&>().allocate(std::size_t{}) must be well-formed when treated as an unevaluated operand.
The size_type parameter type in these guides refers to the size_type member type of the type deduced by the deduction guide.
[edit] Notes
Feature-test macro | Value | Std | Feature |
---|---|---|---|
__cpp_lib_containers_ranges |
202202L |
(C++23) | Ranges-aware construction and insertion; overloads (7-10) |
[edit] Example
#include <unordered_set> int main() { // guide #2 deduces std::unordered_multiset<int> std::unordered_multiset s = {1, 2, 3, 4}; // guide #1 deduces std::unordered_multiset<int> std::unordered_multiset s2(s.begin(), s.end()); }