< cpp‎ | filesystem‎ | path
Defined in header <filesystem>
path operator/( const path& lhs, const path& rhs );
(since C++17)

Concatenates two path components using the preferred directory separator if appropriate (see operator/= for details).

Effectively returns path(lhs) /= rhs.

This function is not visible to ordinary unqualified or qualified lookup, and can only be found by argument-dependent lookup when std::filesystem::path is an associated class of the arguments. This prevents undesirable conversions in the presence of a using namespace std::filesystem; using-directive.


[edit] Parameters

lhs, rhs - paths to concatenate

[edit] Return value

The result of path concatenation.

[edit] Example

#include <iostream>
#include <filesystem>
namespace fs = std::filesystem;
int main() {
    fs::path p = "C:";
    std::cout << "\"C:\" / \"Users\" / \"batman\" == "
              << p / "Users" / "batman" << '\n';

Possible output:

"C:" / "Users" / "batman" == "C:Users\\batman"

[edit] Defect reports

The following behavior-changing defect reports were applied retroactively to previously published C++ standards.

DR Applied to Behavior as published Correct behavior
LWG 3065 C++17 allowed concatenating everything convertible to path in the presence of a using-directive made hidden friend

[edit] See also

appends elements to the path with a directory separator
(public member function) [edit]