C++ Operator Precedence
The following table lists the precedence and associativity of C++ operators. Operators are listed top to bottom, in descending precedence.
||Scope resolution||Left-to-right ➔|
||Suffix/postfix increment and decrement|
||Prefix increment and decrement||Right-to-left ←|
||Unary plus and minus|
||Logical NOT and bitwise NOT|
||Dynamic memory allocation|
||Dynamic memory deallocation|
||Multiplication, division, and remainder|
||Addition and subtraction|
||Bitwise left shift and right shift|
||Three-way comparison operator (since C++20)|
||For relational operators < and ≤ and > and ≥ respectively|
||For equality operators = and ≠ respectively|
||Bitwise XOR (exclusive or)|
||Bitwise OR (inclusive or)|
||Ternary conditional[note 2]||Right-to-left ←|
||Direct assignment (provided by default for C++ classes)|
||Compound assignment by sum and difference|
||Compound assignment by product, quotient, and remainder|
||Compound assignment by bitwise left shift and right shift|
||Compound assignment by bitwise AND, XOR, and OR|
- The operand of
sizeofcan't be a C-style type cast: the expression sizeof (int) * p is unambiguously interpreted as (sizeof(int)) * p, but not sizeof((int)*p).
- The expression in the middle of the conditional operator (between
:) is parsed as if parenthesized: its precedence relative to
When parsing an expression, an operator which is listed on some row of the table above with a precedence will be bound tighter (as if by parentheses) to its arguments than any operator that is listed on a row further below it with a lower precedence. For example, the expressions std::cout << a & b and *p++ are parsed as (std::cout << a) & b and *(p++), and not as std::cout << (a & b) or (*p)++.
Operators that have the same precedence are bound to their arguments in the direction of their associativity. For example, the expression a = b = c is parsed as a = (b = c), and not as (a = b) = c because of right-to-left associativity of assignment, but a + b - c is parsed (a + b) - c and not a + (b - c) because of left-to-right associativity of addition and subtraction.
Associativity specification is redundant for unary operators and is only shown for completeness: unary prefix operators always associate right-to-left (delete ++*p is delete(++(*p))) and unary postfix operators always associate left-to-right (a++ is ((a))++). Note that the associativity is meaningful for member access operators, even though they are grouped with unary postfix operators: a.b++ is parsed (a.b)++ and not a.(b++).
Operator precedence is unaffected by operator overloading. For example, std::cout << a ? b : c; parses as (std::cout << a) ? b : c; because the precedence of arithmetic left shift is higher than the conditional operator.
Precedence and associativity are compile-time concepts and are independent from order of evaluation, which is a runtime concept.
The standard itself doesn't specify precedence levels. They are derived from the grammar.
Some of the operators have alternate spellings (e.g., and for
&&, or for
||, not for
In C, the ternary conditional operator has higher precedence than assignment operators. Therefore, the expression e = a < d ? a++ : a = d, which is parsed in C++ as e = ((a < d) ? (a++) : (a = d)), will fail to compile in C due to grammatical or semantic constraints in C. See the corresponding C page for details.
 See also
a = b
a == b
static_cast converts one type to another related type
C documentation for C operator precedence