std::enable_shared_from_this<T>::operator=
From cppreference.com
< cpp | memory | enable shared from this
enable_shared_from_this& operator=( const enable_shared_from_this &rhs ) noexcept; |
(since C++11) | |
Does nothing; returns *this.
Contents |
[edit] Parameters
rhs | - | another enable_shared_from_this to assign to *this
|
[edit] Return value
*this
[edit] Notes
The exposition-only std::weak_ptr<T> member weak-this
is not affected by this assignment operator.
[edit] Example
Note: enable_shared_from_this::operator= is defined as protected
in order to prevent accidental slicing but allow derived classes to have default assignment operators.
Run this code
#include <iostream> #include <memory> class SharedInt : public std::enable_shared_from_this<SharedInt> { public: explicit SharedInt(int n) : mNumber(n) {} SharedInt(const SharedInt&) = default; SharedInt(SharedInt&&) = default; ~SharedInt() = default; // Both assignment operators use enable_shared_from_this::operator= SharedInt& operator=(const SharedInt&) = default; SharedInt& operator=(SharedInt&&) = default; int number() const { return mNumber; } private: int mNumber; }; int main() { std::shared_ptr<SharedInt> a = std::make_shared<SharedInt>(2); std::shared_ptr<SharedInt> b = std::make_shared<SharedInt>(4); *a = *b; std::cout << a->number() << '\n'; }
Output:
4
[edit] See also
(C++11) |
smart pointer with shared object ownership semantics (class template) |