C++ named requirements: MoveInsertable (since C++11)
Specifies that an object of the type can be constructed into uninitialized storage from an rvalue of that type by a given allocator.
T is MoveInsertable into the container
value_type is identical to
T if, given
||an allocator type|
|| an lvalue of type |
|| the pointer of type |
|| rvalue expression of type |
X::allocator_type is identical to std::allocator_traits<A>::rebind_alloc<T>,
the following expression is well-formed:
std::allocator_traits<A>::construct(m, p, rv);
And after evaluation, the value of
*p is equivalent to the value formerly held by
rv remains valid, but is in an unspecified state.)
X is not allocator-aware, the term is defined as if
A were std::allocator<T>, except that no allocator object needs to be created, and user-defined specializations of std::allocator are not instantiated.
A is std::allocator<T>, then this will call placement-new, as by ::new((void*)p) T(rv). This effectively requires
T to be move constructible.
If std::allocator<T> or a similar allocator is used, a class does not have to implement a move constructor to satisfy this type requirement: a copy constructor that takes a
const T& argument can bind rvalue expressions. If a MoveInsertable class implements a move constructor, it may also implement move semantics to take advantage of the fact that the value of
rv after construction is unspecified.
 See Also