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std::remove_extent

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< cpp‎ | types
 
 
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Defined in header <type_traits>
template< class T >
struct remove_extent;
(since C++11)

If T is an array of some type X, provides the member typedef type equal to X, otherwise type is T. Note that if T is a multidimensional array, only the first dimension is removed.

If the program adds specializations for std::remove_extent, the behavior is undefined.

Contents

[edit] Member types

Name Definition
type the type of the element of T

[edit] Helper types

template< class T >
using remove_extent_t = typename remove_extent<T>::type;
(since C++14)

[edit] Possible implementation

template<class T>
struct remove_extent { using type = T; };
 
template<class T>
struct remove_extent<T[]> { using type = T; };
 
template<class T, std::size_t N>
struct remove_extent<T[N]> { using type = T; };

[edit] Example

#include <algorithm>
#include <iostream>
#include <iterator>
#include <type_traits>
 
template<class A>
    std::enable_if_t<std::rank_v<A> == 1>
print_1d(const A& a)
{
    std::copy(a, a + std::extent_v<A>,
        std::ostream_iterator<std::remove_extent_t<A>>(std::cout, " "));
    std::cout << '\n';
}
 
int main()
{
    int a[][3] = {{1, 2, 3}, {4, 5, 6}};
//  print_1d(a); // compile-time error
    print_1d(a[1]);
}

Output:

4 5 6

[edit] See also

(C++11)
checks if a type is an array type
(class template) [edit]
(C++11)
obtains the number of dimensions of an array type
(class template) [edit]
(C++11)
obtains the size of an array type along a specified dimension
(class template) [edit]
removes all extents from the given array type
(class template) [edit]