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std::remove_reference

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< cpp‎ | types
 
 
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Defined in header <type_traits>
template< class T >
struct remove_reference;
(since C++11)

If the type T is a reference type, provides the member typedef type which is the type referred to by T. Otherwise type is T.

The behavior of a program that adds specializations for remove_reference is undefined.

Contents

[edit] Member types

Name Definition
type the type referred by T or T if it is not a reference

[edit] Helper types

template< class T >
using remove_reference_t = typename remove_reference<T>::type;
(since C++14)

[edit] Possible implementation

template< class T > struct remove_reference      {typedef T type;};
template< class T > struct remove_reference<T&>  {typedef T type;};
template< class T > struct remove_reference<T&&> {typedef T type;};

[edit] Example

#include <iostream>
#include <type_traits>
 
int main() {
    std::cout << std::boolalpha;
 
    std::cout << "std::remove_reference<int>::type is int? "
              << std::is_same<int, std::remove_reference<int>::type>::value << '\n';
    std::cout << "std::remove_reference<int&>::type is int? "
              << std::is_same<int, std::remove_reference<int&>::type>::value << '\n';
    std::cout << "std::remove_reference<int&&>::type is int? "
              << std::is_same<int, std::remove_reference<int&&>::type>::value << '\n';
    std::cout << "std::remove_reference<const int&>::type is const int? "
              << std::is_same<const int,
                              std::remove_reference<const int&>::type>::value << '\n';
}

Output:

std::remove_reference<int>::type is int? true
std::remove_reference<int&>::type is int? true
std::remove_reference<int&&>::type is int? true
std::remove_reference<const int&>::type is const int? true

[edit] See also

checks if a type is either a lvalue reference or rvalue reference
(class template) [edit]
adds a lvalue or rvalue reference to the given type
(class template) [edit]
combines std::remove_cv and std::remove_reference
(class template) [edit]